A function f(x) is not differentiable at x=a if:
lim h-->0 [f(a+h)-f(a)] / h does not exist.
Jei is a derrivative of the name Geraldine and means "One who rules by the spear"
HTML and its derrivative DHTML is used to position information in a web page, and XML is used to describe that information.
Of course.
The Range is the set of all possible output values of a function or relation.
It is quite possible. A well-known example is the fourth parameter of qsort.
From the information provided in the question it is not possible to tell.
The answer is a description, in words, of some function that has been plotted. With no information about the function it is not possible to provide a more useful answer.The answer is a description, in words, of some function that has been plotted. With no information about the function it is not possible to provide a more useful answer.The answer is a description, in words, of some function that has been plotted. With no information about the function it is not possible to provide a more useful answer.The answer is a description, in words, of some function that has been plotted. With no information about the function it is not possible to provide a more useful answer.
No, that is not possible.
Yes, it is possible for a function to have a negative semidefinite Hessian matrix at a critical point.
No. If the range of the first function is not the domain of the second function then the composite function is not defined.
There is no single function. In fact there are infinitely many possible functions.
The range of a function is the set of all possible input values.