Wiki User
∙ 14y agoThe general form that you are trying to get to resembles y = ax + b, where a is the slope of your line and b is the y-intercept. Assuming your equation looks something like
2x + 4y + 2 = 3y + 5
you'll move all of the y's to the left side of the equation, so subtract 3y from 4y to get
2x + y + 2 = 5
Then move everything else to the right side of the equation, so subtract the 2 from the 5 and the 2x, resulting in
y = -2x + 3
The slope (a) is -2 and the y-intercept (b) is 3.
Wiki User
∙ 14y agoIt is the general form of a quadratic equation.
A quadratic equation.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
Solving the equation for "y" gives you the slope-intercept form.
It is the general form of a quadratic equation.
It works out in its general form as: 3x-4y-6 = 0
A quadratic equation.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
Solving the equation for "y" gives you the slope-intercept form.
y = 6/7x+3 General form of the line equation: 6x -7y+21 = 0
x^2+4x+7
No, not if the y is squared. When graphed the equation will not form a straight line.
The equation contains variables which are only raised to the first power.
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