The general form that you are trying to get to resembles y = ax + b, where a is the slope of your line and b is the y-intercept. Assuming your equation looks something like
2x + 4y + 2 = 3y + 5
you'll move all of the y's to the left side of the equation, so subtract 3y from 4y to get
2x + y + 2 = 5
Then move everything else to the right side of the equation, so subtract the 2 from the 5 and the 2x, resulting in
y = -2x + 3
The slope (a) is -2 and the y-intercept (b) is 3.
It is the general form of a quadratic equation.
A quadratic equation.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
Solving the equation for "y" gives you the slope-intercept form.
It is the general form of a quadratic equation.
It works out in its general form as: 3x-4y-6 = 0
A quadratic equation.
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
Solving the equation for "y" gives you the slope-intercept form.
y = 6/7x+3 General form of the line equation: 6x -7y+21 = 0
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
No, not if the y is squared. When graphed the equation will not form a straight line.
x^2+4x+7
The equation contains variables which are only raised to the first power.
3x-6y=-8