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What is the general form of the linear equation that passes through 1-2 and 32?
Wiki User
∙ 9y ago
If you mean points of: (1, -2) and (3, 2) then it works out as 2x-y-4 = 0 in its geneal form
Wiki User
∙ 9y ago
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Is y equals -3 a liner equation?
Yes, it is a linear equation with no slope. The graph is a straight line (parallel to the x-axis) that passes through the y-axis, at {0,-3}
Do all linear equations need to be proportional?
No.A directly proportional graph has an equation of the form y = mx. It always passes through the origin.A linear graph will have an equation in the from y = mx + c. This has a y-intercept at (0, c). It doesn't pass through the origin unless c = 0. The directly proportional graph is a special case of a linear graph.
What is the equation of a line in general form that passes through points (-1 2) and (5 2)?
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
If the graph of a linear equation Ax plus By equals C passes through the origin then will C equal 0?
Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.
How does using the point slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How can you write the equation for a linear function if you know only two ordered pairs for the functionDrag tiles to complete the explanation.?
the Equation of a Line Given That You Know Two Points it Passes Through.
Is y equals -3 a liner equation?
Yes, it is a linear equation with no slope. The graph is a straight line (parallel to the x-axis) that passes through the y-axis, at {0,-3}
Do all linear equations need to be proportional?
No.A directly proportional graph has an equation of the form y = mx. It always passes through the origin.A linear graph will have an equation in the from y = mx + c. This has a y-intercept at (0, c). It doesn't pass through the origin unless c = 0. The directly proportional graph is a special case of a linear graph.
What is the equation of the line in its general form that passes through -2 -3 and is perpendicular to the equation of 4x plus 3y -5 equals 0?
It works out in its general form as: 3x-4y-6 = 0
Which equation represents a line that passes through the point (5, 5) and is perpendicular to the line x + 2y = 10?
General formula
What is the equation of a line in general form that passes through points (-1 2) and (5 2)?
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
A line passes through the origin and has a slope of?
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
If the graph of a linear equation Ax plus By equals C passes through the origin then will C equal 0?
Yes Ax + By = C As the line passes through the origin then x = 0 when y = 0. Substituting gives, 0 + 0 = C therefore C = 0.
How does using the point-slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point - slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point slope form a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
