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3:4 or 75%
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
If you are talking about mass produced bottles then the probability is very low. There would certainly be some form of quality control in the system to ensure the items fall between the tolerances required.
A monohybrid cross is a cross between parents who are heterozygous at one locus; ... The results The wrinkled trait --- which had disappeared in his hybrid ...of them produced both types of seeds in the F3 and - once again - in a 3:1 ratio
25%
3:4 or 75%
It is a 75% chance that the seeds will be round.
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
To predict the traits of the offspring produced by genetic crosses.
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
false
100%
120 on average or 50%. 25% would be homozygous dominant and 25% would be homozygous recessive. The remaining 50% would be heterozygous.
If two squash are heterozygous, it means they have a genotype with different genes. In this case, it would be Wy (a white gene and a yellow gene. y is lowercase because it represents that it is a recessive trait). If the parents are both Wy, if you create a Punnett Square, you get that the genotypes of the offspring will be WW, Wy, Wy, yy. Therefore, the ratio is 1:2:1 (since there are two Wy).
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%