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bbb

In numbering systems greater than decimal (base 10), we use the lowercase letters of the alphabet, in order, to delineate values greater than 9 in a single place. Thus an "a" means that there are 10 of that place value, a "b" means 11, etc.

This is the equivalent of 11 * (12^2) + 11 * (12^1) + 11 * (12^0)

= (11)(144) + (11)(12) + (11) (1)

= 1584 + 132 + 11

= 1727 (base 10)

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Q: What is the greatest 3 digit number in base twelve?

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BBB, which is 123-1 = 1728-1 = 1727 in base 10.

999.

222

You have to specify the base. For example, in base-16, otherwise known as hexadecimal or hex, the greatest 5 digit number is FFFFF.

1112 which, in decimal, is 7

The greatest value a digit can have in base for is 3. Thus the largest three-digit number in base for would be 333. In base 10, this number is 3x16 + 3x4 + 3 = 63 Therefore 63 is the largest digit that would be three digits in base 4.

BBB which, in decimal, is equal to 1727 (= 123 - 1)

Not in a way that would be generally understood. However, it is possible. An 8-digit number in base 10 can be represented by a 5-digit number in base 32. For example, extending the scheme for labeling digits for base 32, VVVVV32 = 3355443110 Similarly, the 8-digit number 33333333 in base 4 is the 5-digit number 65535 in base 10

The largest 4 digit number in base 8 is 77778 (= 409510).

The largest 3-digit number in base 3 is 222. Its decimal equivalent is 26

11432 is a 5-digit number. Without changing base, it cannot be expressed as a 4-digit number.

12 (Twelve).

A three digit number cannot be divisible by a 5 digit number - in any base.

most people are born with ten fingers. truly, if they all had six per finger we'd likely be using base 12, or a twelve digit number system. most people are born with ten fingers. truly, if they all had six per finger we'd likely be using base 12, or a twelve digit number system.

It is 15.

It is its positional place value within a number

3210 in base 3 is 10123 However, if you mean 323 then this is NOT a number. The maximum value each digit of a number can be is one less than the base. In base 3, the maximum value for any digit is 3 - 1 = 2. No digit can be anything other than 0, 1 or 2. Thus 32 (containing the digit 3) cannot be a base 3 number.

The digit to the left has a place value that is "base" times that on the right. Normally, the base is 10.

You cannot. All you can say is that the base will be larger than the largest digit that appears in the number.

It is 15.

1,000 is the lowest base-10 number that requires 4 significant digits. "0,000" is also a 4-digit number, but the only significant digit is the final zero.

9675 is a 4-digit number. It can be written as a 6 digit number in base 5 or 6 or similar. But without knowing which, it makes little sense to do so.

The highest digit is one less than the base used for counting. So in binary (base 2), the highest digit is 1 In octal (base 8), the highest digit is 7 In decimal (base 10), the highest digit is 9 In hexadecimal (base 16), the highest "digit" is 15. The symbols A, B, C, D, E and F represent the "digits" 10, 11, 12, 13, 14 and 15. And so on.

Assuming your problem means 3 hexadecimal digits, we have the largest 3 digit number being "fff". Since f = 16 (base 10), we have that fff(base 16) = 16*16*16(base 10) = 4096 If it's a 3 digit decimal number, then 999, since hex can represent ANY number.

That depends on what base you are using. It could be 1

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