In base ten, there are 9000 four digit number, the numbers are from 1000 to 9999. If you allow leading zeros, then there are 10000 numbers. [0000 - 9999]
With 4 different numbers, 24.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
12 numbers
4,536 whole numbers or mixed numbers. 5,040 pure decimals.
The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.
14
There are infinitely many numbers in each system, however base 10 uses 10 digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} and binary uses 2 digits {0, 1}. The maximum digit is one less than the base.
In base ten, there are 9000 four digit number, the numbers are from 1000 to 9999. If you allow leading zeros, then there are 10000 numbers. [0000 - 9999]
The digit 6 has no meaning in base 4.
In the base-10 system, the 4-digit whole numbers are every number from 1,000 to 9,999. That's 9,000 numbers. If decimals are included, there are a lot more. For example, from .0001 to .9999 alone, there are over 9,000 more.
there are 4 numbers
take 20 blocks group them into sets of 4. How many sets did you make? 20 / 4 = 5
base 4 would use the digits 0,1,2,3 so the first place digit would be 1,2,3 the 2nd place would be 0,1,2,3 and the 3rd place would be 0,1,2,3 3x4x4 =48
There are infinitely many numbers between 34 and 50 and so infinitely many sets of 4 numbers.
With 4 different numbers, 24.
The numbers that fit this criteria are 2, 2, and 8. When you add 2 + 2 + 8, you get 12. This combination of numbers satisfies the condition of having three of the same numbers that add up to 12, without the number being 4.