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First we need to find the L.C.M. of 40, 48 and 60.

40 = 2x2x2x5

48 = 2x2x2x2x3

60 = 2x2x3x5

After taking out common factors, we have

L.C.M. = 2x2x2x3x5x2 = 240

To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.

Remainder = 159

Subtracting this remainder from 9999 we get 9999 - 159 = 9840.

So, the required answer is 9840.

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โˆ™ 2011-05-12 03:33:54
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Sejuti Sarkar

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โˆ™ 2021-06-06 15:22:11
Totally wrong
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Anonymous

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โˆ™ 2020-07-28 09:34:53

40 = 2x2x2x5

48 = 2x2x2x2x3

60 = 2x2x3x5

After taking out common factors, we have

L.C.M. = 2x2x2x3x5x2 = 240

To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.

Remainder = 159

Subtracting this remainder from 9999 we get 9999 - 159 = 9840.

So, the required answer is 9840.

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Q: What is the greatest 4 digit number which is exactly divisible by 40 48 and 60?
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