First we need to find the L.C.M. of 40, 48 and 60.

40 = 2x2x2x5

48 = 2x2x2x2x3

60 = 2x2x3x5

After taking out common factors, we have

L.C.M. = 2x2x2x3x5x2 = 240

To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.

Remainder = 159

Subtracting this remainder from 9999 we get 9999 - 159 = 9840.

So, the required answer is 9840.

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40 = 2x2x2x5

48 = 2x2x2x2x3

60 = 2x2x3x5

After taking out common factors, we have

L.C.M. = 2x2x2x3x5x2 = 240

To find the greatest 4 digit number which is divisible by 240 we divide 9999 by 240.

Remainder = 159

Subtracting this remainder from 9999 we get 9999 - 159 = 9840.

So, the required answer is 9840.

🤓

🤯

🤔

Q: What is the greatest 4 digit number which is exactly divisible by 40 48 and 60?

Write your answer...

99882

9960

999996

The greatest three digit number that is divisible by 7 is 994.

How about: 960

The greatest 4-digit number that is divisible by 16 is 9984

The integers divisible by those 5 numbers are exactly the multiples of 1008. The largest multiple of 1008 which is still a four-digit number is 9*1008 = 9072.

There is no 4-digit number that is divisible by zero.

There is no limit to the number of digits.If, for example, a X is a k-digit number which is divisible by 4 then 10*X is divisible by 4 and 10*X will be a (k+1)-digit number.

96

9999

It is 99992.

998

99,990.

35 x 285 = 9975 The highest three-digit number divisible by 35 is 9975.

10080

It is 99984.

99996

0

The largest 5-digit number divisible exactly by 99 is 99990.

113 x 88 = 9944 The highest four-digit number divisible by 88 is 9944.

A number is divisible by 9 if the sum of its digits is divisible by 9. Thus, the number 99999 is divisible by 9 (the sum of its digits is 45, and it is clearly 11111 * 9), and because 99999 is the largest 5 digit number, it must be the largest 5 digit multiple of 9. 99999 is the greatest no divisible by 9.if u divide it u`ll get 11111.

100015

9990

990