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Q: What is the greatest 5 digit number divisible by 45?

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90000, for example.

90. All numbers divisible by 5 and 9 are multiples of their lowest common multiple. lcm(5, 9) = 45 → need an even two digit multiple of 45, which is 2 x 45 = 90.

50,004There is a method called "casting out nines" that can be used to quickly test if any positive number is divisible by 9. To perform this test add the digits of the number, if the result has more than one digit repeat the addition of the digits, when the result is a single digit if that digit is 9 then the number is divisible by nine.Examples:99999, gives 45, gives 9, is divisible by 912345, gives 15, gives 6, is not divisible by 910008, gives 9, is divisible by 950004, gives 9, is divisible by 930303, gives 9, is divisible by 933633, gives 18, gives 9, is divisible by 9etc.

45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.

If the number is divisible by both 5 and 9, then the number fits into 45 perfectly. 5- If the last digit is 0 or 5 9- If the sum of the digits are divisible by 9 Examples: 61,335, 844,560, 174,555 Non Examples: 4,122, 2085

Related questions

The lowest common multiple of 5 and 9 is 45 and 11 times 45 is 495 which is the greatest 3 digit number divisible by 5 and 9

A number is divisible by 9 if the sum of its digits is divisible by 9. Thus, the number 99999 is divisible by 9 (the sum of its digits is 45, and it is clearly 11111 * 9), and because 99999 is the largest 5 digit number, it must be the largest 5 digit multiple of 9. 99999 is the greatest no divisible by 9.if u divide it u`ll get 11111.

999990

Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.

You just need a 4 digit number divisible by 5x9 ie by 45, so 4500 will do.

90000, for example.

45 and 90

The LCM of 5 and 9 is 45 and so 45*22 = 990

You would say to yourself:-- If it has to be divisible by 5 and 9, then it's divisible by 45.-- The biggest 3-digit number is 999.-- 999 divided by 45 is 22.2-- So if I multiply 45 by only 22 and leave off the 0.2,I'll get the biggest one that's less than 999.-- 45 x 22 = 990 .

Count by 45. 45,90,135,180 so you have two choices.

It is easier to find the lowest common number, then getting the largest multiple of that that is under 10000. The LCM is 4680, x2 is 9360.

90. All numbers divisible by 5 and 9 are multiples of their lowest common multiple. lcm(5, 9) = 45 → need an even two digit multiple of 45, which is 2 x 45 = 90.

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