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Q: What is the greatest number possible with these digits 3 71 5?

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Using only the digits and the basic operators of arithmetic, 71. If other operators are allowed then 71! = 8.5*10101 approx, or 85 googol is one possible answer.

The greatest factor of any number is the number itself. The greatest common factor of 71 and 92 is 1.

By simply rearranging the digits the answer is 8710. However, 80^71 is very much larger, a lot larger than a googol. And there are other possible answers that are bigger still.

The greatest prime number of 5141 is 71.

71 is a prime number, so its only factors are 1 and 71. Unless n is a multiple of 71, the greatest common factor is 1. If n is a multiple of 71, the greatest common factor is 71.

The greatest number formed by rearranging the digits is 97514. There are, however, much larger even number. For example, 954^71 is a number that is larger than googol squared. And 4^(71^95) is very much larger. <<>> 97541> 97514 . . . How about 4 to the power 5 to the power 7 to the power 91. Or how about 4! to the power 5! to the power 7! to the power 91!.

There are actually three valid answers: 17, 53, and 71 All are prime and all have digits adding to 8.

It is 1 because 71 is a prime number

71 is a single number and so there is no "between" possible!

The GCF of 35 and 71 is 1 because 71 is a prime number.

71 is a prime number, and divisible only by 1 and itself

Take your pick: It could be 33: the only composite number with repeated digits It could be 71: the only prime number It could be 4: the only square number It could be 106: the only composite number with all different digits.

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