After 3 half lifes there will 45 counts per hour (360 -> 180 -> 90 ->45). Therefore 3 half lifes equals 18 hours. One half life is therefore 6 hours.
Because not only one element in a chemical compound counts for the chemical/physical prperties.
A banana is not an element. You would have to determine the specific elements present and then figure out what their proton and neutron counts are.
Counts and No Counts - 1918 was released on: USA: 15 April 1918
The cast of Counts and No Counts - 1918 includes: Joe Rock
There must be the same total number of each element on each side of the equation.Working through each element in turn:1. count the total number of each element on each side (don't forget to include any coefficients found so far as multipliers)2. If the counts are different then:divide the counts by their highest common factor if it is greater than 1;multiply coefficient of each compound containing the element on the left by the count of the right;multiply coefficient of each compound containing the element on the right by the count of the left;3. repeat the above until all the counts are the same 4. if there is a common factor (greater than 1) of all the coefficients on both sides divide the coefficients by this common factor.Examples (as I can't do subscripts, they are shown in brackets after the element):CH(4) + O(2) → CO(2) + H(2)OC: both sides have 1, leave equation aloneH: left 4, right 2; hcf(4, 2) = 2, so counts become L: 4÷2 = 2, R: 2÷2=1; equation becomes CH(4) + O(2) → CO(2) + 2H(2)OO: left 2, right 4; hcf(2, 4) = 2, so counts become Left 1, Right 2; equation becomes CH(4) + 2O(2) → CO(2) + 2H(2)OC: both sides 1, leave the equation aloneH: both sides 4, leave the equation aloneO: both sides 4, leave the equation alone→ balanced equation is CH(4) + 2O(2) → CO(2) + 2H(2)OCH(4) + O(2) → CO + H(2)OC: both sides have 1, leave equation aloneH: left 4, right 2; hcf(4, 2) = 2, so counts become Left 2, Right 1; equation becomes CH(4) + O(2) → CO + 2H(2)OO: left 2, right 3; hcf(2, 3) = 1, so counts stay the same; equation becomes CH(4) + 3O(2) → 2CO + 4H(2)OC: left 1, right 2; hcf(1, 2) = 1, so counts stay the same, equation becomes 2CH(4) + 3O(2) → 2CO + 4H(2)OH: both sides have 8, leave equation aloneO: both sides have 6, leave equation alone[as only first element had coefficients changed, the equation is now balanced, repeating the check would show both sides of the elements are now equal with C: 2. H: 8, O: 6]→ balanced equation is 2CH(4) + 3O(2) → 2CO + 4H(2)O
Carbon-12 is the most common form of Carbon and therefore, counts for most of the atomic mass.
You may be thinking of counts in yarn, where counts can indicate the number of twists per inch in the spin.
Brycen Counts is 5' 7".
Counts of Hainaut was created in 1071.
Love Counts was created in 2005.
Citizenship Counts was created in 2008.
Climate Counts was created in 2007.