Different people find different things hard. So a problem that is hard for someone may seem easy to you and one that you think is hard may be easy for someone else. It is, therefore, not possible to answer the question.
This one. The problem is trying to prove that a infinite number of pairs of prime numbers exist. It has recently been proved as shown by this article on nature.com. This is one of the oldest math problems in history, going clear back to the ancient Greeks.
n+1=n solve for n.
What is hard for some people may not be hard for others. So there is really no answer to this question.
For many 6th graders, one of the hardest math problems may involve solving multi-step word problems that require a combination of operations such as addition, subtraction, multiplication, and division. Another challenging concept could be understanding and applying fractions, decimals, and percentages in real-world situations. Additionally, grasping the concept of algebraic expressions and equations may also pose a significant challenge for some 6th graders.
Different people find different problems hard and so it is difficult to answer the question.
That's hard to say.
Foucault's last conundrum.Fermi's last theromExact value of Pi.
The hardest math problem ever Also, according to True Jackson V.P, the answer is 16. I paused the screen showing the problem, and x=16
Anyone can if they work hard at it.
This one. The problem is trying to prove that a infinite number of pairs of prime numbers exist. It has recently been proved as shown by this article on nature.com. This is one of the oldest math problems in history, going clear back to the ancient Greeks.
n+1=n solve for n.
This one may be confusing its 1.12933E.2394 + 9.1879E98.234 Yet this is hard
What is hard for some people may not be hard for others. So there is really no answer to this question.
For many 6th graders, one of the hardest math problems may involve solving multi-step word problems that require a combination of operations such as addition, subtraction, multiplication, and division. Another challenging concept could be understanding and applying fractions, decimals, and percentages in real-world situations. Additionally, grasping the concept of algebraic expressions and equations may also pose a significant challenge for some 6th graders.
Oh, dude, 20 cents is just 0.20 in decimals. It's like the easiest math problem ever, right? So, if you're ever in a situation where you need to convert your pocket change into decimals, now you know!
Different people find different problems hard and so it is difficult to answer the question.
That's a easy one chickens