that's a big cup!
supposing it's a perfect cylinder, it's V=(pi)r2h remember?
256 = 3.142 x 16 X h
256 = 50.272 X h
Solve for h (divide both sides by 50.272) 256/50.272 = 5.0922978...
h = 5.0922978... round to wherever you need. don't forget to label your units of measurement (inches)
A cone that has a radius of 1 inch and a height of 6 inches has a volume of 6.28 cubic inches.
Volume = pi*r2*h = 282.7433 cubic inches
if radius is 2.5 inch, volume is pi x radius squared x height = 157.07 cubic inches. Make sure your units are consistent. Then you can solve for height = 8.0 inches
A sphere cannot have a 17 inch height, if it has a 6 inch radius. If it has a 6 inch radius, the height (diameter, in this case), would be 2 times the radius, which is 12. If it was a sphere with 6 inch radius (and not using height), then you use the formula, 4/3(pi)r^3. = 4/3 * pi * 6^3 = 288 pi ≈ 904.779 inches cubed. Dingbot is: 1. over-sensitive to long answers, 2. correct to ping over-exact answers pasted from [Windows] Calculator. Folks, 4 to 6 significant figures are enough for us engineers and mechanics - any more is just bragging.
A cone with a base radius of 8 inches and a height of 8 inches has a volume of 536.17 cubic inches.
A cylinder with a radius of 4.5 inches and a height of 3 inches has a volume of 190.85 cubed inches.
The volume of a cylinder is πr2h. r is the radius, which is half the diameter, which is 1.5 inches, and h is the height, which is 0.5 inches. Thus, the volume of the cylinder is 3.534291735 inches cubed.
The volume of a cylinder with a 9-inch height and a 3-inch radius is: 254.47 cubic inches.
A cone that has a radius of 1 inch and a height of 6 inches has a volume of 6.28 cubic inches.
Volume = pi*r2*h = 282.7433 cubic inches
if radius is 2.5 inch, volume is pi x radius squared x height = 157.07 cubic inches. Make sure your units are consistent. Then you can solve for height = 8.0 inches
The volume of the sphere is 38792.38 inches cubed Formula: Volume = PI x diameter cubed / 6 Step 1) 3.14 x 42 cubed / 6 = 38792.38609 Volume = 38792.38 inches cubed (the power of 3) +++ I have tested the above values but the standard formula for the volume of a sphere is 4/3.pi.(radius cubed).
Volume of the sphere: 4/3*pi*0.25 cubed = 1/48*pi cubic inches
A sphere cannot have a 17 inch height, if it has a 6 inch radius. If it has a 6 inch radius, the height (diameter, in this case), would be 2 times the radius, which is 12. If it was a sphere with 6 inch radius (and not using height), then you use the formula, 4/3(pi)r^3. = 4/3 * pi * 6^3 = 288 pi ≈ 904.779 inches cubed. Dingbot is: 1. over-sensitive to long answers, 2. correct to ping over-exact answers pasted from [Windows] Calculator. Folks, 4 to 6 significant figures are enough for us engineers and mechanics - any more is just bragging.
A cone with a base radius of 8 inches and a height of 8 inches has a volume of 536.17 cubic inches.
A cylinder has a volume equal to the area of its circular face multiplied by its height. Area of a circle is (pi)*r^2, where "r" is the radius of the circle. Since the diameter is twice the radius, the radius in this case is 1.25 inches. Area = (pi)*(1.25in)^2 = 4.9087in^2 This, multiplied by the height of the can, yields a volume of (5in)*(pi)*(1.25in)^2 = 24.5437in^3 or about 24.5 inches cubed.
Volume for a cylinder is:Volume = (base) x (height) = (π x radius2) x (height)V = bh = πr2hSo, with π = 3.14 (approximately):Volume = (3.14 x 32) x (8) = 225.08 in2