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What is the height of a triangle with the area of 104 yd and a base of 13 yd?
Wiki User
∙ 11y ago
Area = 1/2*b*h
104 yd2 = 1/2(13 yd)h
multiply through by 2
208 = 13h
208/13 = h
Height = 16 yards
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Wiki User
∙ 11y ago
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What is the height of a triangle if area is 104 inches squared and the base is 13 inches?
Area = 1/2*13*height = 104 Multiply both sides by 2: 13*height = 208 Divide both sides by 13: height = 16 inches Check: 1/2*13*16 = 104 square inches
What is the area of a trapezoid with base length 14 centimeters and 12 centimeters and the a height of 8 centimeters?
Area = 1/2*(14+12)*8 = 104 square cm
What is the area of a triangle with sides 14MM 15MM and 19MM?
Using trigonometry the area of the triangle works out as 104 square MM rounded to the nearest whole number
What is the area of a trapezoid with bases of 12 and 14 and height of 8?
Area = 1/2*(14+12)*8 = 104 square cm
What is the base and exponent of 104?
For 104 the base is 10 and the exponent is 4.
If an obtuse triangle has a base that is 13 inches and height that is 16 inches what is the area of the triangle?
the equation for area of a triangle is A = 1/2 bhso the answer is . . . 1/2 x 13 x 16 = 104
What is the height of a triangle if area is 104 inches squared and the base is 13 inches?
Area = 1/2*13*height = 104 Multiply both sides by 2: 13*height = 208 Divide both sides by 13: height = 16 inches Check: 1/2*13*16 = 104 square inches
The base of a triangle is 5m longer than its height and its area is 52m squared what is the base?
A = (bh)/2Since the base b of the triangle is 5 cm longer than its height, then we can express the height in terms of base. So we have:A = [b(b-5)]/2 (multiply by 2 to both sides)2A = b2 - 5b (substitute 52 for A)104 = b2 - 5b (subtract 104 to both sides)b2 - 5b - 104 = 0 (solve for b using the quadratic formula)b = [5 ± √[5 - 4(1)(-104)]]/2(1)b = [5 ± √(5 + 416)]/2 (since the length is always positive)b = (5 + 21)/2b = 13Thus, the base is 13 m long.
What is the area of a trapezoid with base length 14 centimeters and 12 centimeters and the a height of 8 centimeters?
Area = 1/2*(14+12)*8 = 104 square cm
What is the area of a triangle with sides 14MM 15MM and 19MM?
Using trigonometry the area of the triangle works out as 104 square MM rounded to the nearest whole number
What is the area of a trapezoid with bases of 12 and 14 and height of 8?
Area = 1/2*(14+12)*8 = 104 square cm
A triangle with two congruent sides and an angle of 104 degrees is?
A triangle with two congruent sides is isosceles. A triangle with an angle of 104 degrees is obtuse. So you would have an obtuse isosceles triangle.
What is the base and exponent of 104?
For 104 the base is 10 and the exponent is 4.
What is the measure of the vertex angle of an isosceles triangle if one of its base angles measure 38degrees?
104 degrees: 180 - (2 x 38)
What is the surface area of a rectangular prisam with a length of 6 a width of 2 and a height of 5?
104 square units.
How is the radius of a cylinder if the total surface area is 104 pi feet squared and the height is 9 feet?
the answer is impossible . ha
If a square prism has a volume of 104 cubic centimeters and a height of eight centimeters how would you find find the area?
Given: V = 104 cm3, h = 8 cm Find: Area Solution: Since V = Bh, where B is the area of the base, and h is the height of a prism, then B = V/h substitute the given values: B = 104 cm3/8 cm B = 13 cm2, which tells us that the length side of the square base equals square root of 13. The surface area of a prism = L.A. + 2B, where L.A. is the lateral area of the prism. L.A. = pH, where p is the perimeter of the base. Since p = 4(square root of 13) cm, h = 8cm, and B = 13 cm2, we have: Surface Area = pH + 2B = [4(square root of 13) cm](8 cm) + 2(13 cm2) = 115.38 cm2 + 26 cm2 = 141 cm2 Thus, the surface area of the prism is approximately 141 cm2.
