A = (bh)/2
Since the base b of the triangle is 5 cm longer than its height, then we can express the height in terms of base. So we have:
A = [b(b-5)]/2 (multiply by 2 to both sides)
2A = b2 - 5b (substitute 52 for A)
104 = b2 - 5b (subtract 104 to both sides)
b2 - 5b - 104 = 0 (solve for b using the quadratic formula)
b = [5 ± √[5 - 4(1)(-104)]]/2(1)
b = [5 ± √(5 + 416)]/2 (since the length is always positive)
b = (5 + 21)/2
b = 13
Thus, the base is 13 m long.
Its height is: 8 feet
this is 5cm (:
Easy! It's 5.
Area of a triangle = 1/2 x base x altitude(height)On putting given values, we get45cm2 = 1/2 x 6cm x height(altitude)cm45 = 3 x altitudealtitude = 15 cmAnswer to the question is 15cm.
132 ft
Is the height 9m or 8m? Area of triangle = Base x Height / 2 If the height is 9m... The area is 37m squared If the height is 8m... The area is 24m squared.
Height = 8 cm
The squared area of a triangle is half of its base times its perpendicular height. Or as: 0.5*base*perpendicular height = area of a triangle
27cm squared
42units squared :)
The area is 48 units squared.
the height of a triangle is three feet longer than the base. The area of the triangle is 35 square feet. Find the height andbase of the triangle
Area of a triangle = 1/2 * base * heightWe have,Area = 28 cm squared, base = 8cmthen,28 = 1/2 * 8 * h28 = 4*hh = 7cm
The area of a triangle is base x height ... soo...... 9 x 16 =144 cm squared =)
The area is 80 squared units.
Area = 0.5*base*height 28 = 0.5*8*height So height = 7 inches.
48 units squared.