Common factors of 18, 30, and 48 are: 1, 2, 3, and 6.
The common factors of 18 and 48 are: 1, 2, 3, and 6
The greatest common factor is 6
The same as the highest common factor of 18 and 12 (where 12 is the remainder of the division of 48 by 18).
66
12
16
The common factors of 48, 72, and 112 are the numbers that can evenly divide each of these numbers without leaving a remainder. To find the common factors, you can first list the factors of each number. The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72. The factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112. The common factors of 48, 72, and 112 are 1, 2, 4, 8, and 16.
The greatest common factor is 48
'6' Method Factors of 18 are 2,3,6,9, Factors of 30 are 2,3,5,6,10,15, Factors of 48 are 2,3,4,6,8,12,24, 2,3 & 6 appear in all three factorisations. Hence '6' being the largest /highest number , then '6' is the HCF (Highest Common Factor).
The common factors are: 1, 2, 3, 6.
It seems like you're asking for the highest common factor (HCF) of 18, 30, and 48. To find the HCF, we can factorize each number: 18 = 2 * 3^2 30 = 2 * 3 * 5 48 = 2^4 * 3 Now, we look for the highest power of common factors: The common factors are 2 and 3. The highest power of 2 that appears in all three numbers is 2^1. The highest power of 3 that appears in all three numbers is 3^1. Therefore, the HCF of 18, 30, and 48 is 2 * 3, which is equal to 6