It would be extremely large, if it exists.
Briefly:
It is known that all perfect (even) numbers are generated by the formula 2p−1(2p−1) whenever 2p−1 is prime.
When 2p−1 is prime, it is known as a Mersenne prime. There are currently (as of October 2009) only 47 known Mersenne primes, the largest of which has almost 13 million digits.
It is unknown if there are further Mersenne primes between the 40th one and the current 47th one.
It is unknown if there are infinitely many Mersenne Primes.
It is also unknown if there are any odd perfect numbers, but the evidence so far is that the first one to exist must be extremely large.
So there may, or may not, be a 100th perfect number.
There are only 47 known perfect (even) numbers - one for each of the 47 Mersenne primes.
The Hundredth even number is 200200
The hundredth place in the number 0.46735 is the number 6.
Round this number to the nearest hundredth 0.3636 ? Round this number to the nearest hundredth 0.3636 ?
In this case, the hundredth would be the number "7." This number rounded to the nearest hundredth would simply remain as 2.37
5.48
0.86 the 0.8 is tenth the 0.06 is hundredth * * * * * But, to the nearest hundredth, the number is 0.86
5.83 rounded to nearest hundredth.
58.635 → 58.64 to the nearest hundredth
6.14
3.60
420.33
tenth: 30.1 whole number:30 hundredth:30.09