5 units. (Using the Pythagorean Theorem, a²+b²=c², means that 4²+3²=x². 4²=16, 3²=9, so 16+9=25. x²=25, so x=5.)
It will be a right angled triangle with sides of 3 and 4 units with an hypotenuse of 5 units in length.
Its hypotenuse is 5 units in length
From the Pythagorean theorem, if the unknown hypotenuse is called h, h2 = 162 + 122, or h = sq rt (256 + 144) = 20 units. (This is a 3-4-5 triangle enlarged by a factor of 4.)
It completely depends on what type of triangle it is.
The hypotenuse is 15. The Pythagorean Theorum states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides; in other words, if c is the length of the hypotenuse, and a and b are the lengths of the other two sides:a2 + b2 = c2In this case, a = 9 (a2 = 81) and b = 12 (b2 = 144), and a2 + b2 = 81 + 144 = 225. But we know that this is also equal to c2. If c2 = 225, then c = √225 = 15.Also, just a little thought reveals that this triangle is a "3-4-5" triangle. For any right triangle with non-hypotenuse sides of length 3 and 4 units, the hypotenuse will be 5 units in length. Because units are arbitrary, this relationship extends to multiple of 3, 4, and 5. 9 and 12 are 3 times 3 and 4. So the hypotenuse is 3 times 5, or 15.
It will be a right angled triangle with sides of 3 and 4 units with an hypotenuse of 5 units in length.
If the two adjacent sides of a triangle are 3' and 4', the hypotenuse is: 5'
One particular triangle with sides measuring 3, 4 and 5 units is a right angled triangle. Such a triangle meets with Pythagoras's Theorem "The square on the hypotenuse is equal to the sum of the squares on the other two sides." In this case, the hypotenuse measures 5 units. Then, 52 = 32 + 42 25 = 9 + 16 = 25
Its hypotenuse is 5 units in length
From the Pythagorean theorem, if the unknown hypotenuse is called h, h2 = 162 + 122, or h = sq rt (256 + 144) = 20 units. (This is a 3-4-5 triangle enlarged by a factor of 4.)
Using Pythagoras:- 242+242 = 1152 and the square root of this is the length of the hypotenuse which is 24*sq rt 2 which is about 33.941 units to 3 d.p.
It completely depends on what type of triangle it is.
The hypotenuse is 15. The Pythagorean Theorum states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides; in other words, if c is the length of the hypotenuse, and a and b are the lengths of the other two sides:a2 + b2 = c2In this case, a = 9 (a2 = 81) and b = 12 (b2 = 144), and a2 + b2 = 81 + 144 = 225. But we know that this is also equal to c2. If c2 = 225, then c = √225 = 15.Also, just a little thought reveals that this triangle is a "3-4-5" triangle. For any right triangle with non-hypotenuse sides of length 3 and 4 units, the hypotenuse will be 5 units in length. Because units are arbitrary, this relationship extends to multiple of 3, 4, and 5. 9 and 12 are 3 times 3 and 4. So the hypotenuse is 3 times 5, or 15.
Construct a right angle triangle with a base of 3 units, a height of 4 units with a hypotenuse of 5 units and then:- Enlarge the base to 3 by 3 square units = 9 squares Enlarge the height to 4 by 4 square units = 16 squares Enlarge the hypotenuse to 5 by 5 square units = 25 squares Thus proving Pythagoras' theorem: a2+b2 = c2 whereas a and b are the sides of the triangle with c being its hypotenuse or longest side
It is 7.62 units of length, approx.
According to the "3-4-5" law of right triangles, if the two sides of the triangle are 3 units and 4 units, the hypotenuse must be 5 units. So a diagonal must be 15 inches. The sides are 3 * 3 and 3 * 4, so the diagonal is 3 * 5.
If you mean vertices of (-4, 2) (-4, 5) and (3, 2) then it will form a right angle triangle when plotted on the Cartesian plane with sides of 3 units by 7 units by square root of 58 or about 7.616 units which is its hypotenuse and longest side