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What I helps you find the area under the curve y x3 4x-3.6?
Integration.
What I helps you to find the area under the curve y x3 4x - 3.6?
"integration"
What I helps you to find the area under the curve y x3 4x-3.6?
if this is for www.mymaths.co.uk, integration is all you need. best regards, lokilotus
What I helps you to find the area under the curve y x3 4x 3.6?
well, it would help to clarify your question, but integrate the fuction and solve on the interval given
X equals acos3m y equals bsin3m find area under curve?
(3ab*pi)
How do you find the area enclosed by the curve y equals 7x-x2-10 and the x-axis?
The area under a curve (between it and the x-axis) is found by integrating the curve: area = ∫ y dx The area enclosed between the curve and the x-axis is bounded by where the curve meets the x-axis. 7x - x² - 10 = -(x - 2)(x - 5) = 0 → The curve meets the x-axis at x = 2 and x = 5 The area between the limits is the difference between the value of the the integral at the limits. → A = ∫ y dx = ∫ 7x - x² - 10 dx = (7/2)x² - (1/3)x³ - 10x + c → A = ((7/2)×5² - (1/3)×5³ - 10×5 + c) - ((7/2)×2² - (1/3)×2³ - 10×2 + c) = 4.5
What i helps you to find the area under the curve Y equals x3 plus 4x-3.6?
integration FINALLY THERE IS AN ANSWER!!!!!!!!!!!!! it really is the answer! type in: integration ,AND IT WORKS! by the way to prove I'm not lying, the answer to the first mymaths puzzle is the guy in the middle of the three guys (the guy with a white hat Btw)
What is a bean curve?
A bean curve is a mathematical curve with the formula x^4 + x^2 y^2 + y^4 = x(x^2 + y^2).
Find the area in the first quadrant bounded by the curve y squared equals 4x the x axis and the line x equals 2?
It is 8*sqrt(2)/3 = 3.7712 approx.
How do you find points of a curve?
If it passes through zero, then that could be a first point (0, 0). If you have the function of the curve, you can get other points by plugging in numbers for x and solving for y, giving you more coordinates in the form of (x, y). Suppose the curve is given in the parametric form as: x = f(t), y = g(t), a < t < b. Then giving different values of t and finding the corresponding values of x and y, we can get different points (x, y) on the curve.
Distinguish between demand curve and engel curve?
The difference is the Y- axis. In the case of the Demand curve the Y - axis is the retail price of the good. On the Engel's curve the Y -axis is the amount of income over a set period of time.
How can we find the coordinates of x in the intersection of line and curve?
For example, the equation of a line: y = ax + b. the equation of a curve: y = cx2 + dx + e ax + b = cx2 + dx + e (solve for x)
