The input force is where you put force in. This will be the push with the perosn in the wheelchair. The output force is...um...um....um........um..oh right. The output force it where see ya. nvm
-- angle the ramp makes with the ground -- weight of the piano -- height above ground at the top of the ramp -- horizontal distance between the beginning and end of the ramp If the question included any one of these pieces of information, an answer could be calculated. But with only the information given, it can't be.
You need to know the coefficient of friction between the ramp and the cart.
If it is 0.6m (long?) then how can it be 2 m high? Also, if friction is involved, this will affect the amount of force.
To generate a ramp signal in MATLAB, you can use the "linspace" function to create a vector of evenly spaced values, and then multiply it by the desired slope and offset. Here is an example code that generates a ramp signal with a slope of 2 and an offset of 1: t = linspace(0, 1, 100); % Create a vector of 100 evenly spaced values between 0 and 1 ramp_signal = 2*t + 1; % Multiply the vector by 2 and add 1 to generate the ramp signal with slope 2 and offset 1
Divide the height of the ramp by the length of the ramp (rise over run).
Allows mechanical advantage, > Output force = Input force * (distance travelled up and parallel to ramp / vertical distance travelled)
It is output/input x 100, i.e. 60%.
The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.
The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.
The height.=====================Answer #2:The mechanical advantage.
The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.
No, landlords are not required to pay for a ramp for handicapped renters. A person always have the option to move.
The effort needed would increase.
the input distance is the distance that you push the object up the ramp. this distance allows you to go up how ever far the tallest point of the ramp is. this is the output distance.
A ramp makes work easier by letting you elevate an object with less input force.
To make the job easier for you and can help you with the heavy lifting.
(Presuming no losses due to friction.) Work done at input = Work done at output So > Work done at output = force * distance = 25 * 5 = 125 joules So > Work done at input (125 joules) = 11 * distance So > distance = 125 / 11 = 11.3636 .. .. .. .. metres.