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The input force is where you put force in. This will be the push with the perosn in the wheelchair. The output force is...um...um....um........um..oh right. The output force it where see ya. nvm

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Q: What is the input and output force of a handicapped ramp?
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What is the mechanical advantage of a ramp if you and two friends apply a force of 425 N to push a piano up a 2.0m long ramp?

-- angle the ramp makes with the ground -- weight of the piano -- height above ground at the top of the ramp -- horizontal distance between the beginning and end of the ramp If the question included any one of these pieces of information, an answer could be calculated. But with only the information given, it can't be.


What is the magnitude of the external force f necessary to hold the cart motionless at point c...2 kg. cart going up ramp of 10 meters slanted at 30 degrees. the ramp is 5 meters high?

You need to know the coefficient of friction between the ramp and the cart.


What is the work and force of 1kg being pushed up a 0.6 m ramp and a height of 2 m?

If it is 0.6m (long?) then how can it be 2 m high? Also, if friction is involved, this will affect the amount of force.


What is the Matlab code to generate a ramp signal?

To generate a ramp signal in MATLAB, you can use the "linspace" function to create a vector of evenly spaced values, and then multiply it by the desired slope and offset. Here is an example code that generates a ramp signal with a slope of 2 and an offset of 1: t = linspace(0, 1, 100); % Create a vector of 100 evenly spaced values between 0 and 1 ramp_signal = 2*t + 1; % Multiply the vector by 2 and add 1 to generate the ramp signal with slope 2 and offset 1


How do you work out the gradiant on a ramp?

Divide the height of the ramp by the length of the ramp (rise over run).

Related questions

What are the functions of an incline plane?

Allows mechanical advantage, > Output force = Input force * (distance travelled up and parallel to ramp / vertical distance travelled)


If the input work was 1000 and the output work was 600 what was the mechanical efficiency of using the ramp?

It is output/input x 100, i.e. 60%.


How would the input force needed to push a wheelchair up a ramp change if you increase the height of the ramp but not its length?

The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.


How would the input force needed to push a wheelchair up a ramp change if you increased the height of the ramp but not it's length?

The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.


A ramp increases what of the input force?

The height.=====================Answer #2:The mechanical advantage.


How would the input force needed to push a wheelchairup a rampchange if you increased the height of the ramp but not it's length?

The input force would increase as the height of the ramp increased. It wouldn't matter the distance. Ask me another one.


Must landlords pay for a ramp for handicapped renters?

No, landlords are not required to pay for a ramp for handicapped renters. A person always have the option to move.


How would the input force needed to push a wheelchair up a ramp change if you increase the height of the ramp but not its lenght?

The effort needed would increase.


Is there a Distance in and distance out of an inclined plane?

the input distance is the distance that you push the object up the ramp. this distance allows you to go up how ever far the tallest point of the ramp is. this is the output distance.


How does a ramp help to make work easier?

A ramp makes work easier by letting you elevate an object with less input force.


Will a ramp decrease the size of the output force needed to lift A BOX?

To make the job easier for you and can help you with the heavy lifting.


How long of a ramp would you need to lift 25n up 5 meters but only strong enough to lift 11n?

(Presuming no losses due to friction.) Work done at input = Work done at output So > Work done at output = force * distance = 25 * 5 = 125 joules So > Work done at input (125 joules) = 11 * distance So > distance = 125 / 11 = 11.3636 .. .. .. .. metres.