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What is the integer if the product of two consecutive odd integers is one less than three times their sum?
Ddgourmet
Numbers are n and n + 2, so product = n2 + 2n and sum = 2n + 2.
ie n2 + 2n + 1 = 6n + 6
or n2 - 4n - 5 = 0
Factors are (n + 1)(n - 5) making n = 5 and the integers 5 & 7.
Check: 5 x 7 = 35; 5 + 7 = 36. OK
There is also an answer of n = -1, making the integers -1 and 1, product being -1 and sum zero.
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How do you translate the product of two consecutive multiple of three integers into a algebraic expression?
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