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The indefinite integral of (6x4-2)2(24x) dx.

The simplest way to do this is to expand the multiplication in the integrand until its a single polynomial comprised of only terms added or subtracted together.

(6x4-2)2=(6x4-2)(6x4-2)=36x8-24x4+4=4(9x8-6x4+1)

(24x)(4(9x8-6x4+1))=96x(9x8-6x4+1)=96(9x9-6x5+x)

From here on out, its simple polynomial antiderivation. The 96 is a constant that can be factored out and ignored. So the antiderivative would be:

96*[9x9/10 - x6 + x2/2] + C

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Q: What is the integral of 6x to the 4th power - 2 squared times 24xdx?
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