42069
3X
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
7
To find the product of (x+4) and (x^2-3x+2), you need to distribute each term in the first expression to each term in the second expression. This results in x*(x^2-3x+2) + 4*(x^2-3x+2). Simplifying further, you get x^3-3x^2+2x + 4x^2-12x+8. Combining like terms gives you the final answer: x^3+x^2-10x+8.
(3x^2 - 4y^2)(3x^2 + 4y^2)
4
3x^2 + x + 2x^2 = 5x^2 + x
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
9x
3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11
2x^8 x 3x^2 x -4x = -24x^11
(3x + 2)(x + 5)
That can be factored to (3x - 5)(3x - 5) or (3x - 5)2
The degree is the term with the greatest exponent So in 3x^2 + 5x + 7 The degree is 2 since the highest exponent is 2 If there is no power sign assume that the number is to the 1 power 3x^2 + 5x + 7 can also be written as 3x^2 + 5x^1 + 7^1 ^ = power of
x(3x+6) or 3x(x+2). Id recomend the second one.