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1. its -4 over x

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Q: What is the inverse function for 4 over x?
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What is the inverse of the function f(x) 4x?

if f(x) = 4x, then the inverse function g(x) = x/4


Is it possible for a fourth degree function to have an inverse that is a function?

In order for a fourth degree function to have an inverse function, its domain must be restricted. Otherwise the inverse function will not pass the vertical-line test.Ex.f(x) = x^4 (x>0), the original functionf-1(x) = x ^ (1/4), the inverse


What is the difference between a reciprocal function and an inverse function?

A reciprocal function will flip the original function (reciprocal of 3/5 is 5/3). An inverse function will change the x's and y's of the original function (the inverse of x<4,y>8 is y<4, x>8). Whenever a function is reflected over the line y=x, the result is the inverse of that function. The y=x line starts at the origin (0,0) and has a positive slope of one. All an inverse does is flip the domain and range.


Which function is the inverse function of y 5x - 4?

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What is the inverse of the function f of x equals x to the power of one over x?

The inverse is not a function because it fails the vertical line test.


What is the inverse of the function f(x) 2 - x?

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What is the inverse function of y equals 2x minus 4?

To find the inverse of a function, you replace x with y and y with x. Here, y=2x-4 would become x=2y-4. Now, we solve for y. 2y=x+4. y=(x/2)+4, and that is the inverse equation.


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What is the inverse of the function f(x) 4x 8?

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Why is the graph of an inverse of a function flipped over the line y x instead of another line?

Because the inverse of a function is what happens when you replace x with y and y with x.


What function is the inverse of a quadratic function?

If the quadratic function is f(x) = ax^2 + bx + c then its inverse isf'(x) = [-b + +/- sqrt{b^2 - 4*(c - x)}]/(2a)


Why is the graph of an inverse of a function flipped over the line y equals x instead of another line?

Because the inverse of a function is what happens when you replace x with y and y with x.