The inverse for f(x) = 4x + 8 isg(x) = x/4 - 2
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If: 4x+(-12) = 8 then 4x = 20 and x = 5
The derivative of 2x2 + 4x + 8 is 4x+4.
y = x² - 2x - 8 Swap x and y to find the inverse: x = y² - 2y - 8 Now get y by itself: y² - 2y = x + 8 (Complete the square): y² - 2y + 1 = x + 9 (y - 1)² = x + 9 y - 1 = ±√(x + 9) y = 1 ±√(x + 9) Then there are two functions: f(x) = 1 - √(x + 9) and f(x) = 1 + √(x + 9) but an inverse can only be one function. The functions above are a mirror image of the original function, but it is not an inverse (graph these functions). There is no inverse. Everything above is completely wrong. This is the inverse: (x+8)/2 I don't know where the x² came from in the first answer, but to work out the question as asked: if y=2x-8 y+8 = 2x (y+8)/2 = x so, as the above answer stated, (x+8)/2 is the answer.
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
4x + 5y = -8 is an equation with two variables. While you can solve for y = something, you won't come up with a single number. For example, 4x + 5y = -8 5y = -4x - 8 y = -4x/5 - 8/5. And you can do the same for x = something in terms of y.