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What is the kinetic energy of a 60 grain bullet traveling at 3000 feet per second?
Wiki User
∙ 14y ago
60 grains = 0.003888 kg 3000 feet per second = 914.4 m/s Kinetic Energy = 0.5 x Mass x Velocity^2 KE = 0.5 x 0.003888 x 914.4^2 = 1625.43158784 Joules
Wiki User
∙ 14y ago
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A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?
A 60 gram bullet fired from a gun with 3150 joules of kinetic energy has a velocity of 324.04 meters per second or 1,063.12 feet per second. (This is about 725mph).
How much energy is 500 joules?
500 joules is equal to 368.78 ft-lbf. For example, an object has 500 joules of kinetic energy, when its mass is 10 kg (~22 lbs) and it is traveling at 10 m/s (36 km/h or ~38.2 ft/s). Second example: The muzzle energy of a traveling 9mm bullet is around 500 joules. Third example: An object with mass of 5kg (11 lbs) and which is raised at 10 metres (32.8 ft) has around 500 joules of potential energy. So, 500 joules is quite much. Getting hit with an object which has 500 joules of kinetic energy can be lethal.
How is kinetic energy and momentum similar?
Answer #1:Kinetic energy is the energy possessed by an object due to its movementor motion. Momentum on the other hand, is the quantity of motion of anobject that is a product of its mass and velocity.====================================Answer #2:Kinetic Energy = 1/2 M V2kg-m2/s2 (Newton-meter = Joule)Momentum = M V kg-m/s (Newton-second)Numerical Difference = (1/2 M V2) - (M V) = (M V) x (1/2V -1) .
What is The kinetic energy of a 25 gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
What is the energy of a system by virtue of its motion?
That's called kinetic energy. The formula is: Kinetic energy = (1/2) x mass x velocity2. If mass is in kilograms, and velocity (or speed, really) in meters per second, the energy will be in Joules.
A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?
A 60 gram bullet fired from a gun with 3150 joules of kinetic energy has a velocity of 324.04 meters per second or 1,063.12 feet per second. (This is about 725mph).
What If you have four balls all traveling at 5 meters per second which one has the most kinetic energy?
If several objects have the same speed and the same velocity,then each has the same kinetic energy.
How much kinetic energy does an electron traveling in free space at 32415.926535 ms have?
You are supposed to use the formula for kinetic energy. As a reminder, the formula is (1/2)mv2. If the speed is in meters per second, and the mass in kilograms, the energy will be in joules.
Which has the most kinetic energy a 1000 kg car traveling 30 ms or a car traveling 45 ms?
WOW, 5 MILES PER SECOND. I guess that I would have to calculate the miles per hour. To do this, we must multiply 5 miles per second times 3600(the number of seconds in an hour). That is 18000 miles per hour. I like to work in the SI system, so by converting this to meters per second, we get 8.04672E3 meters per second. Kinetic energy is defined as one half mvsquared. The Kinetic Energy is equal to 3.2374E10 Joules.
What is The kinetic energy of a 25-gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
How is kinetic energy and momentum similar?
Answer #1:Kinetic energy is the energy possessed by an object due to its movementor motion. Momentum on the other hand, is the quantity of motion of anobject that is a product of its mass and velocity.====================================Answer #2:Kinetic Energy = 1/2 M V2kg-m2/s2 (Newton-meter = Joule)Momentum = M V kg-m/s (Newton-second)Numerical Difference = (1/2 M V2) - (M V) = (M V) x (1/2V -1) .
How much energy is 500 joules?
500 joules is equal to 368.78 ft-lbf. For example, an object has 500 joules of kinetic energy, when its mass is 10 kg (~22 lbs) and it is traveling at 10 m/s (36 km/h or ~38.2 ft/s). Second example: The muzzle energy of a traveling 9mm bullet is around 500 joules. Third example: An object with mass of 5kg (11 lbs) and which is raised at 10 metres (32.8 ft) has around 500 joules of potential energy. So, 500 joules is quite much. Getting hit with an object which has 500 joules of kinetic energy can be lethal.
What has more kinetic energy a 0.0018-kg bullet traveling at 402 ms or a 6.8 107-kg ocean liner traveling at 10 ms 19 knots?
For an object of mass m (measured in kilograms, kg) travelling at a speed v (measured in metres per second, m s-1), assuming that v is well below the speed of light, the kinetic energy E (measured in joules, J) is given by:E = 1/2 m v2So for the bullet, m = 0.0018 kg, and v = 402 m s-1:E = 1/2 x 0.0018 kg x (402 m s-1)2= 145.4436 JFor the ocean liner, assuming m = 6.8 x 107 kg (68 000 000 kg), and v = 10 m s-1:E = 1/2 x 68 000 000 kg x (10 m s-1)2= 3 400 000 000 JSo the bullet has a kinetic energy of around 145 joules, and the ocean liner has a kinetic energy of 3.4 billion joules. To answer the question, the ocean liner has more kinetic energy than the bullet.
What is The kinetic energy of a 25 gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
What is the mathmetical formula for kinetic energy?
Kinetic Energy = 1/2(mass in kilograms)(meters per second)2
What is the energy of a system by virtue of its motion?
That's called kinetic energy. The formula is: Kinetic energy = (1/2) x mass x velocity2. If mass is in kilograms, and velocity (or speed, really) in meters per second, the energy will be in Joules.
Is touching a kinetic energy?
Kinetic energy is the energy of motion. Your touching finger has mass and is moving some meters per second, so that motion is kenetic energy.
