0
What else can I help you with?
What is the kinetic energy in joules of a 0.02 kg bullet traveling 300 miles per second?
The kinetic energy of the bullet can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass and v is the velocity. Plugging in the values, KE = 0.5 * 0.02 kg * (300 m/s)^2 = 900 J. So, the kinetic energy of the bullet is 900 joules.
A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?
To determine the velocity of the bullet, we can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity. Given that the kinetic energy is 3150 joules and the mass is 60 grams (which is 0.06 kg), we can rearrange the formula to solve for v. Plugging in the values, we get 3150 = 0.5 * 0.06 * v^2. Solving for v, we find that the velocity of the bullet is approximately 250 meters per second.
Can kinetic energy be measured?
Kinetic energy can be measured, but the act of measuring it changes the kinetic energy of the object you are measuring. For example, you can measure the kinetic energy of a bullet fired from a gun by allowing the bullet to strike an known object and then measure the deflection/deformation of the target object. While it is possible to measure the kinetic energy of the bullet this way, the bullet itself is no longer moving after this measurement, and therefore your measurement caused a change in the bullet's kinetic energy. . Kinetic energy (E) can be calculated without changing the kinetic energy of the object under observation if you know the mass (m) of the object and if you can observe or calculate its velocity (v) using the equation E=(1/2)m/v2.
When the coaster is at the top of the second hill what is the relationship between kinetic energy and potential energy?
At the top of the second hill, the coaster has maximum potential energy and minimum kinetic energy. As the coaster descends, potential energy decreases while kinetic energy increases due to the conversion of potential energy into kinetic energy.
What is The kinetic energy of a 25 gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
What is the kinetic energy in joules of a 0.02 kg bullet traveling 300 miles per second?
The kinetic energy of the bullet can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass and v is the velocity. Plugging in the values, KE = 0.5 * 0.02 kg * (300 m/s)^2 = 900 J. So, the kinetic energy of the bullet is 900 joules.
What is kinetic energy of 124 grain 9mm bullet?
The kinetic energy of a 124 grain (8.04 grams) 9mm bullet traveling at typical handgun velocities (around 1,200 feet per second) would be approximately 400 foot-pounds.
A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?
To determine the velocity of the bullet, we can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity. Given that the kinetic energy is 3150 joules and the mass is 60 grams (which is 0.06 kg), we can rearrange the formula to solve for v. Plugging in the values, we get 3150 = 0.5 * 0.06 * v^2. Solving for v, we find that the velocity of the bullet is approximately 250 meters per second.
Can kinetic energy be measured?
Kinetic energy can be measured, but the act of measuring it changes the kinetic energy of the object you are measuring. For example, you can measure the kinetic energy of a bullet fired from a gun by allowing the bullet to strike an known object and then measure the deflection/deformation of the target object. While it is possible to measure the kinetic energy of the bullet this way, the bullet itself is no longer moving after this measurement, and therefore your measurement caused a change in the bullet's kinetic energy. . Kinetic energy (E) can be calculated without changing the kinetic energy of the object under observation if you know the mass (m) of the object and if you can observe or calculate its velocity (v) using the equation E=(1/2)m/v2.
How much kinetic energy does an electron traveling in free space at 32415.926535 ms have?
You are supposed to use the formula for kinetic energy. As a reminder, the formula is (1/2)mv2. If the speed is in meters per second, and the mass in kilograms, the energy will be in joules.
Which has the most kinetic energy a 1000 kg car traveling 30 ms or a car traveling 45 ms?
WOW, 5 MILES PER SECOND. I guess that I would have to calculate the miles per hour. To do this, we must multiply 5 miles per second times 3600(the number of seconds in an hour). That is 18000 miles per hour. I like to work in the SI system, so by converting this to meters per second, we get 8.04672E3 meters per second. Kinetic energy is defined as one half mvsquared. The Kinetic Energy is equal to 3.2374E10 Joules.
What is The kinetic energy of a 25-gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
What If you have four balls all traveling at 5 meters per second which one has the most kinetic energy?
All four balls would have the same kinetic energy since kinetic energy is determined by both the mass and velocity of the object. If all four balls have the same mass and velocity, their kinetic energy would be equal.
When the coaster is at the top of the second hill what is the relationship between kinetic energy and potential energy?
At the top of the second hill, the coaster has maximum potential energy and minimum kinetic energy. As the coaster descends, potential energy decreases while kinetic energy increases due to the conversion of potential energy into kinetic energy.
What is The kinetic energy of a 25 gram bullet traveling at 500 ms?
Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules
How is kinetic energy and momentum similar?
Answer #1:Kinetic energy is the energy possessed by an object due to its movementor motion. Momentum on the other hand, is the quantity of motion of anobject that is a product of its mass and velocity.====================================Answer #2:Kinetic Energy = 1/2 M V2kg-m2/s2 (Newton-meter = Joule)Momentum = M V kg-m/s (Newton-second)Numerical Difference = (1/2 M V2) - (M V) = (M V) x (1/2V -1) .
What has more kinetic energy a 0.0018-kg bullet traveling at 402 ms or a 6.8 107-kg ocean liner traveling at 10 ms 19 knots?
For an object of mass m (measured in kilograms, kg) travelling at a speed v (measured in metres per second, m s-1), assuming that v is well below the speed of light, the kinetic energy E (measured in joules, J) is given by:E = 1/2 m v2So for the bullet, m = 0.0018 kg, and v = 402 m s-1:E = 1/2 x 0.0018 kg x (402 m s-1)2= 145.4436 JFor the ocean liner, assuming m = 6.8 x 107 kg (68 000 000 kg), and v = 10 m s-1:E = 1/2 x 68 000 000 kg x (10 m s-1)2= 3 400 000 000 JSo the bullet has a kinetic energy of around 145 joules, and the ocean liner has a kinetic energy of 3.4 billion joules. To answer the question, the ocean liner has more kinetic energy than the bullet.
