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Kinetic Energy - EK (J) = 1/2mv2

Where m = mass (kg)
v = velocity (ms-1)

Therefore a 6.8 kg block travelling at 6 ms-1 has kinetic energy equal to:

(6.8/2) x 62

= 3.4 x 36

=122.4 Joules

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Q: What is the kinetic energy of a block if a 6.8 kilogram block is sliding down a horizontal frictionless surface at a constant speed of 6 meters per second?
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Related questions

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What is the net force acting if an object is moving along a surface with a constant acceleration?

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A particle is projected at 60 degree to the horizontal with a kinetic energy k the kinetic energy at highest point is?

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A horizontal force of 100 N pushes a box across a floor at a constant speed. what is the force of friction acting on the box?

If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force


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