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The key to solving this kind of problem is to use the largest digit you possibly can, starting at the left. For example, the largest even digit is 8, so you start with an 8. For the next digit - the second from left - you can't repeat the 8, nor any odd digit, so you need to use the next-largest even digit.

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Q: What is the largest number that can be formed with no odd numbers and without repeating any digit?

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86420

987654

96425 Larger numbers can be made by cascading the powers, but not on here because the notation won't take it.

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Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.

9876543210, without using any mathemeatical operations.

976542

I think the answer is: 976542

Two versions of this question have been merged ... the one that asks forthe smallest 5-digit number, and the one that asks for the largest.If we're talking integers (whole numbers), then-- the largest 5-digit number with no repeating digits is 98,765 .-- the smallest one is 10,234 .-- If decimals are included, then the largest number is the same,but the smallest one is .01234 .

502 205 250 520 4 numbers. If a leading zero is allowed then you can have 052 and 025 for 6 numbers.

There are 25 such numbers.

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