The largest three-digit number is 999. To determine if it is a multiple of three, we can check if the sum of its digits (9 + 9 + 9 = 27) is divisible by three. Since 27 is divisible by three, 999 is the largest three-digit multiple of three.
996
The largest two-digit multiple of 5 is 95. This is because the multiples of 5 within the two-digit range start from 10 and go up to 95, with each multiple increasing by 5. The next multiple, 100, is a three-digit number, so 95 remains the largest two-digit multiple.
9984 is the largest 4-digit multiple of 32
-70
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The largest five-digit multiple of three is 99,999
998
996
The largest two-digit multiple of 5 is 95. This is because the multiples of 5 within the two-digit range start from 10 and go up to 95, with each multiple increasing by 5. The next multiple, 100, is a three-digit number, so 95 remains the largest two-digit multiple.
999 = 27 x 37
9984 is the largest 4-digit multiple of 32
-70
999 is a three-digit multiple of 9
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99990 Note that if you add 11 to my answer you get a 6-digit number therefore it must be the largest 5-digit whole multiple of 11.
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
16*625 = 10000 so the largest 4-digit multiple must be 16*624 = 9984