999 is a three-digit multiple of 9
Wiki User
∙ 8y agoAnonymous
999 is three-digit of multiplr of 9
-5
Using prime factorization, there are 2 three digit numbers with 9 factors: 512 and 768. There are no three digit numbers with 10 or more prime factors. 512=2^9 and 768=3*2^8
Here are two digit numbers that are divisible by both 6 and 9: 18 (which is the least common multiple) 36 54 72 90
It is 9
4, 8, 12, 16, 20, 24, 28, 32, and 36 are the first 9 multiples of 4.
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
9 isn't prime, but one three-digit multiple of 18 is 108.
108 is a multiple of 9 because 12 times 9 = 108
There isn't one.
54
90
The least three-digit number that is divisible by both 5 and 9 is 135.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
If two and three can go into that number,then it is a multiple of six. It is a multiple of six if BOTH of the following statements are true: 1) The last digit (ones place) is 0, 2, 4, 6, or 8. 2) When you add all the digits together, you get a multiple of 3. For example, 39 is not a multiple of 6 because the last digit is 9. But, 36 is a multiple of 6 because the last digit is 6 and 3+6=9 and 9 is divisible by 3.
The question asserts something that is not true. For example, 2000 - 1000 = 1000. 1000 is not a multiple of 9.
Yes, it is. It can be determined in moments, without doing the division, by calculating the core digit of the number, which is 9. Every number with a core digit value of 9 is a multiple of 9, and therefore a multiple of 3.
All numbers divisible by 9 are divisible by 3, so you want all multiples of 9 that are 5 digit numbers. 10000 ÷ 9 = 11111/9 → first multiple of 9 that is a 5 digit number is 1112 x 9 = 10008 100000÷ 9 = 111111/9 → last multiple of 9 that is a 5 digit number is 11111 x 9 = 99999 → there are 11111 - 1112 + 1 = 10,000 five digit numbers that are divisible by 9 (and 3). I'll let you work some out (hint: multiple any number between 1112 and 11111 inclusive by 9).