There are two ways to think of this question, if the triangles don't have to intersect then the answer is zero. If the triangles have to intersect, then the minimum number of points is one, if the triangles meat at vertex to edge or vertex to vertex.
The least number of obtuse triangles, if all possible triangles are drawn for n points in a plane, is zero. If all the n points lie in a straight line, no triangles are possible and so no obtuse triangles are able to be drawn; thus for any number n, there is a possibility that no obtuse triangles can be drawn, so the least possible number of obtuse triangles drawn is zero.
Perpendicular lines intersect at one point only.
Perpendicular lines are lines that always intersect either at just one point, two points or several more.
It is 8 triangles
Yes, but only if they are mutually coincident.
A polygon...
The smallest number of triangles that you could divide a nonagon into is seven.
2 points
All acute triangles have 3 interior angles and 3 exterior angles. This is true for all triangles.
You need at least four triangles, or at least three trapeziums. Or two triangles and one trapezium.
the answer is three i say that because triangles are pointy there are three points an there all closed so its 3 angles
yes, three points in the least number of points that can be used to define a plane. if you used two points you would only have a line, and one point is a point