1,000,000 or, if they need to be different, then 1,023,456.
It is .56789
What is the least possible 6 digit odd number with only using 1 to 9 once
9999999999 100000000
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
236789
1111, unless you allow negative number. In that case, the answer is -9999.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
There are eighteen of them.
ten factorial = 10! = 3,628,800
Assuming leading zeros are not permitted, then: If repeats are not allowed there are 30 possible numbers. If repeats are allowed there are 60 possible numbers.
6,561