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What is the length and width of a rectangle that's area is 60 square cm and it's perimeter is 38 cm?
Wiki User
∙ 14y ago
Let the width be x and the length be y:
xy = 60
2x+2y = 38
Divide all terns in the bottom equation by 2:
xy = 60
x+y = 19 => x = 19-y
Substitute the value of x in the bottom equation into the top equation:
(19-y)y = 60
19y-y2 = 60
Rearrange the equation into a quadratic:
-y2+19y-60 = 0
Solve by factoring or with the help of the quadratic equation formula:
(-y+4)(y-15) = 0
So y = 15 or y = 4 it must be the former because it's larger
Therefore: width = 4 cm and length = 15 cm
Wiki User
∙ 14y ago
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