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0.5 acres = 21,780 square feet.So you know that (length) times (width) must be 21,780 but there are noother constraints on what the dimensions must be. There are an infinite numberof possible length/width combinations.
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
If the land area of 5 acres is a square (each side equal length) then the perimeter would be 1,866.76 feet.
A rod....5 1/2 feet
OK so we have two formulas: Length = width + 5 (since legth is 5 more than width) length + width + length + width = perimeter= 82 (form. for perm.) so we can replace every instance of "length" with "width + 5" since they are the same. width + 5 + width + width + 5 + width = 82 4xwidth + 10 = 82 4X width = 72 width = 23 so now go back and replace "width" with 23. length = 23 + 5 length = 28 There you go.
1 acre = 4840 sq yd = 9 x 4840 = 43560 sq ft5 acres = 5 x 43560 = 217800 sq ft.If the plot of land is 186' wide then the length = 217800 ÷ 186 = 1170.97' (2dp)
0.5 acres = 21,780 square feet.So you know that (length) times (width) must be 21,780 but there are noother constraints on what the dimensions must be. There are an infinite numberof possible length/width combinations.
Area is defined as Length times Width 1 Acre (43,560 square feet) is a piece of land whose Length times Width is 43,560. Or if we take the square root of 43,560 we get 208.7 In other words if a piece of land is 208.7 feet on one side and 208.7 feet on another side this would be 43,560 square feet. So if area is 5 square acres. picture a tract of land that is 208.7 feet by 1043.5 (5 X 208.7) feet.
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
If the land area of 5 acres is a square (each side equal length) then the perimeter would be 1,866.76 feet.
A rod....5 1/2 feet
Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m
OK so we have two formulas: Length = width + 5 (since legth is 5 more than width) length + width + length + width = perimeter= 82 (form. for perm.) so we can replace every instance of "length" with "width + 5" since they are the same. width + 5 + width + width + 5 + width = 82 4xwidth + 10 = 82 4X width = 72 width = 23 so now go back and replace "width" with 23. length = 23 + 5 length = 28 There you go.
3x^2 plus 5x
The length of the length will be 5 and the width will be 25.
Infinite combinations of length/width will result in 5 acres. Some exampes to consider: If you assume it is a square piece of property, then it is 467 feet on each side. If you assume it is a long rectangular piece of property with say, 100 feet on the road, then the sides would be 2187 feet long.
width=5 length=12