Let the length be x -3 and the width be x:-
2(x -3 +x) = 74
2x -6 +2x = 74
4x = 80
x = 20
Therefore: length = 17 cm and width = 20 cm
Check: 17 +17 +20 +20 = 74 cm
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
You don't have enough information to find the exact length of the width, but the width has to be less then 7.5 if it smaller then the length.
80cm.
The length is 4 cm, the width is 26 cm.
8X36
length is 3 and width is 9
4
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
Perimeter = 2*(Width + Length) So 40 = 2*(8 + Length) 20 = 8 + Length Length = 12.
You don't have enough information to find the exact length of the width, but the width has to be less then 7.5 if it smaller then the length.
60 and 62
Let L be the length of the rectangle and W the width, then L = 2W - 3. The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6 But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4 The width of the rectangle is 4".
80cm.
The length is 4 cm, the width is 26 cm.
8X36
The dimensions work out as length = 9 and width = 5
Given: p = 26cm and 2x width - 5cm = length p = 2(a+b) = 26cm; a+b = 13cm 2x6-5=7 The sides of the rectangle are: width 6cm and length 7cm