L + W = P/2 = 30. L = W + 5 so L = 17.5 and W = 12.5
The perimeter is 60 inches
The length is 20 units and the width is 10 units
The perimeter of a rectangle is 2 x (length(L) + width). 150 = 2(L + 30) = 2L + 60 2L = 150 - 60 = 90 L = 45
The dimensions of the rectangle are 21 units by 9 units
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
The perimeter is 60 inches
20 cm
The length is 20 units and the width is 10 units
The perimeter of a rectangle is 2 x (length(L) + width). 150 = 2(L + 30) = 2L + 60 2L = 150 - 60 = 90 L = 45
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
The dimensions of the rectangle are 21 units by 9 units
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
The length of the length will be 5 and the width will be 25.
60 and 62
There's no such thing as the length of a pentagon. But I don't think that'swhat you're really asking.A pentagon has five sides. If the sum of their lengths (perimeter) is 60, thenthe average length of the sides is 12.
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
A rectangle has 4 sides. Let the width of the rectangle be y. As the length of the rectangle is twice its width, it is 2y. The sum of the 2 sides that are the width: 2 * y = 2y The sum of the 2 sides that are the length: 2y * 2 = 4y The perimeter equals the 2 widths and the 2 breadths: 2y + 4y = 6y The perimeter: 6y = 60 cm So: y = 10 cm The length is 2y = 2 * 10 cm = 20 cm Answer: 20 cm