sqrt(262 - 102) = sqrt(676 - 100) = sqrt(576) = 24 feet.
If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
Suppose the other leg is x. Then the hypotenuse is x+2 So, by Pythagoras, (x+2)2 = 82 + x2 or, x2 + 4x + 4 = 64 + x2 so 4x = 60 so x = 15 and the hypotenuse is 17
third leg 5, area 30
my name is bdub and the answer is 5 dubass
4.930517214 cm (with the help of Pythagoras)
The length of the hypotenuse of a triangle with one leg 19 cm and the other leg eight cm is: 20.62 cm
6
The length of the missing leg will be 18 units.
A right triangle has a hypotenuse of 13 cm and one leg that measures 12 cm What is the length of the other leg?
The hypotenuse must be longer than the other other leg.
9
The length of the other leg is: 35.6 cm
If the other leg has length X. Knowing the rule for triangles a^2+b^2=c^2 and that hypotenuse is x+2 10^2 + X^2 = (X+2)^2 you can solve to find X = 24 and the hypotenuse is 26.
square root of 46
There is a famous theorem that you use to solve this problem, namely the Pythagorean theorem which says that the square on the hypotenuse is equal to the sum of the squares on the opposite sides. (The hypotenuse is the longest side; the other sides are commonly called legs.) If you know the hypotenuse and one leg you can find the other leg by simple algebra. Just subtract the square of the leg you know from the square of the hypotenuse and take the square root of this difference. Bingo! You have your answer.
Suppose the other leg is x. Then the hypotenuse is x+2 So, by Pythagoras, (x+2)2 = 82 + x2 or, x2 + 4x + 4 = 64 + x2 so 4x = 60 so x = 15 and the hypotenuse is 17
third leg 5, area 30