It is 10 feet
around 34ft
11 yards 1 foot
8000lbs I have a 1988 34ft
34*34 = 1156 square feet
For area measurements, you multiply the length by the width. Here the calculation gives you an answer of 408 square feet. Divide by 9 to get 45.33 square yards.
Volume of a pyramid = 1/3*base area*height
198
charlie butcher is known as the brummy legend of kingsheath and he is funny as he used to be and still is the class clown and aparently his penis is 30ft long and suprisingly and even scarilly 34ft wide its said that wen he cumsthe women explodescharlie butcher is known as the brummy legend of kingsheath and he is funny as he used to be and still is the class clown and aparently his penis is 30ft long and suprisingly and even scarilly 34ft wide its said that wen he cumsthe women explodescharlie butcher is known as the brummy legend of kingsheath and he is funny as he used to be and still is the class clown and aparently his penis is 30ft long and suprisingly and even scarilly 34ft wide its said that wen he cumsthe women explodes
30 feet. And you don't have to round it to the nearest foot. It's exactly 30 feet.
sqrt(40'3" * 30'3") = sqrt(40.25 ft * 30.25 ft) = sqrt(40.25*30.25) ft = 34.89 ft or 34ft 10.7inches (approx) That would be the geometric mean of the two lengths.
volume = 23 x 34 x 1/12 = 65.17 cubic feet which is 65.17/27 = 2.41 yards or 6516 pounds at 100 pounds per cubic foot
The length of a quarter wave for constructing one end of a dipole is: 234/MHz = feet of wire. For instance if you have an 80 meter ham radio transceiver and want to construct a dipole to match a frequency of 3.56 MHz (the low power calling frequency) then 234/3.56 = 65.7 feet Next buy a spool of speaker wire, mark off 65 and 3/4 feet, and pull apart the two wires until you reach the mark. Now you have a half wavelength dipole that resonates near 3.56 MHz. Start broadcasting in Morse code and I will meet you on the air! Sandy, KB3EOF