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The altitude forms a right angle triangle with half the side length and one side as the hypotenuse.

Using Pythagoras:

(½side)² + altitude² = side²

→ altitude² = side² - ¼side²

→ altitude² = ¾side²

→ altitude = (√3)/2 × side

→ altitude = (√3)/2 × 6 = 3√3 ≈ 5.2

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Q: What is the length of the altitude of an equilateral triangle with sides of length 6?
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