If it's a right angle triangle and you know its base and height then use Pythagoras' theorem to find the length of its hypotenuse.
Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
12/25 = 2/y so y = 2*25/12 = 25/6 = 4.166... units.
The perimeter is the sum of its 4 sides and its area is length times width
length of a side.If a side Y long. Surface area =Y x Y x 6
5xy
side across from 30: 1/2 the hypontenuse side across from 60: the length of the side across from 30, times the square root of 3 side across from 90: the hypotenuse
3y - 3
The formula to find the hypontenuse (c) of a right triangle if you know the lengths of the other two sides (a, b) a2 + b2 = c2
multiply the x-length and the y-length and 2
Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
12/25 = 2/y so y = 2*25/12 = 25/6 = 4.166... units.
x=length of square x multiplied by y = area of square y=width of square width multiplied by length = area
The perimeter of a rectangle is equal to 2*length + 2* width. In this case, we will say 2x + 2y = p = 48. Since the length is equal to 3 times the width, the equation now becomes p = 6*y + 2*y, or just p = 8y. Now since p =48, y must equal 6. And since the length is three times the width (y), the length is 18.
== == It depends actually. If you were given a value that is a height and want to find the forearm length from that then the forearm length would go on the Y axis (because it is dependant on the height) and the height on the X-axis. If you are given a value that is the forearm length and you want to know the height then you will put height on the Y-axis and the forearm length on the X-axis.
The perimeter is the sum of its 4 sides and its area is length times width
4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
length of a side.If a side Y long. Surface area =Y x Y x 6