4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
81.
4x2-x+2x2 is 6x2-x when simplified
false, in order to be one 8 would have to be a square number which it is not. So the constant term in the trinomial would need to be 4, 9, 16 etc.
It could be either of them.
4(x + 1)(x + 1)
The area is 4x2 square units
false!
It is; (2x+4)^2.
Each side of the square is 2x+1.5 and its area is (2x+1.5) squared
16
Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)
c = 25 4x2 + 20x + 25 (2x + 5)(2x + 5)
4x2-42x+110 = (2x-10)(2x-11) when factored
64
Y
81.
4x2 plus 3=11