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What is the length of the hypotenuse of the right triangle ABC round the answer to one decimal place?
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∙ 14y ago
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What is the length of the hypotenuse rounded to one decimal place?
opposite^2+adjacent^2=hypotenuse^2 ____________ X=/hypotenuse^2 One decimal place would be, for example. 22.7 cm
What is the length of the ABC hypotenuse rounded to one decimal place?
You can make it whatever length you like by selecting the other sides appropriately.
What is length of the equal sides of an isosceles triangle where the two equal angles are 20 degrees and the third side is 12?
Treat it as being two right angled triangles by halving the base and use the cosine ratio to find its hypotenuse (which will be one of the equal sides) cosine = adjacent/hypotenuse hypotenuse = adjacent/cosine hypotenuse = 6/cosine 20 degrees = 6.385066635 The length of the equal sides = 6.4 units correct to one decimal place.
What is the hypotenuse of a right angle triangle where A equals 7m and B equals 6.4m?
Pythagoras' theorem: A2+B2 = C2 (which is the hypotenuse) 72+6.42 = 89.96 square metres. The square root of 89.96 = 9.484724561 metres Answer: 9.5 metres correct to one decimal place.
How would you construct a right triangle given the length of a leg and the radius of the circumscribed circle?
To construct a right triangle given the radius of the circumscribed circle and the length of a leg, begin with two ideas. First, the diameter of the circle is equal to twice the radius. That's pretty easy. Second, the diameter of the circle is the length of the hypotenuse. The latter is a key to construction. Draw your circle, and draw in a diameter, which is the hypotenuse of the right triangle, as was stated. Now set you compass for the length of the leg of the triangle. With this set, place the point of the compass on one end of the diameter (the hypotenuse of your triangle), and draw an arc through the circumference of the circle. The point on the curve of the circle where the arc intersects it will be a vertex of your right triangle. All that remains is to add the two legs or sides of the triangle. Draw in line segments from each end of the hypotenuse (that diameter) to the point where your arc intersected the curve of the circle. You've constructed your right triangle. Note that any pair of lines that is drawn from the ends of the diameter of a circle to a point on the curve of the circle will create a right triangle.
What is the length of the hypotenuse rounded to one decimal place?
opposite^2+adjacent^2=hypotenuse^2 ____________ X=/hypotenuse^2 One decimal place would be, for example. 22.7 cm
Can you make a rectangle out of two triangles and a square?
Sure, place a triangle's hypotenuse (longest side) on the other triangle's hypotenuse, that will give either a square or a rectangle. Then place the square on one end of the rectangle. For this to work though, the length of the square's side HAS to equal the length of the triangles hypotenuses, and likewise each triangle's hypotenuse much equal the length of a side of the square. Hope this is clear.
What is the length of the ABC hypotenuse rounded to one decimal place?
You can make it whatever length you like by selecting the other sides appropriately.
If the lengths of the two sides of a right triangle on either side of the 90 degree angle are 1100 inches and 990 inches what is the length of the remaining side the hypotenuse?
The length of the hypotenuse of a right triangle is the square root of the sum of the squares of the other two sides. In our case H = √ (11002 + 9902) 11002 = 1,210,000 9902 = 980,100 1,210,000 + 980,100 = 2,190,100 √ 2,190,100 = 1,479.89864517811, or 1,479.9 rounded to one decimal place.
What is length of the equal sides of an isosceles triangle where the two equal angles are 20 degrees and the third side is 12?
Treat it as being two right angled triangles by halving the base and use the cosine ratio to find its hypotenuse (which will be one of the equal sides) cosine = adjacent/hypotenuse hypotenuse = adjacent/cosine hypotenuse = 6/cosine 20 degrees = 6.385066635 The length of the equal sides = 6.4 units correct to one decimal place.
Is a equals 6cm find the area of the equilateral triangle round the answer to one decimal place?
For an equilateral triangle with side length a, area = (a²√3)/4, which for a= 6cm is 15.6 cm² [rounded to 1 decimal place]
What is the hypotenuse of a right angle triangle where A equals 7m and B equals 6.4m?
Pythagoras' theorem: A2+B2 = C2 (which is the hypotenuse) 72+6.42 = 89.96 square metres. The square root of 89.96 = 9.484724561 metres Answer: 9.5 metres correct to one decimal place.
How would you construct a right triangle given the length of a leg and the radius of the circumscribed circle?
To construct a right triangle given the radius of the circumscribed circle and the length of a leg, begin with two ideas. First, the diameter of the circle is equal to twice the radius. That's pretty easy. Second, the diameter of the circle is the length of the hypotenuse. The latter is a key to construction. Draw your circle, and draw in a diameter, which is the hypotenuse of the right triangle, as was stated. Now set you compass for the length of the leg of the triangle. With this set, place the point of the compass on one end of the diameter (the hypotenuse of your triangle), and draw an arc through the circumference of the circle. The point on the curve of the circle where the arc intersects it will be a vertex of your right triangle. All that remains is to add the two legs or sides of the triangle. Draw in line segments from each end of the hypotenuse (that diameter) to the point where your arc intersected the curve of the circle. You've constructed your right triangle. Note that any pair of lines that is drawn from the ends of the diameter of a circle to a point on the curve of the circle will create a right triangle.
What are the uses triangle in maths?
maybe if some place were in a triangle shape and if you had a sort out the length of the place they use it
How do you find a centre of circle when we have a right triangle and a circle We need to find the centre of circle. Can someone please help me?
If the sides of the triangle are equal in length to the radius of the circle, then you can simply place the two ends of the hypotenuse on the perimeter of the circle, and it's remaining corner will lie at the circle's center.
Find the area of an equilateral triangle that has a perimeter of 21 inches Round the answer to one decimal place?
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
If a 6 cm find the area of the equilateral triangle. Round the answer to one decimal place.?
To find the area of an equilateral triangle, you can use the formula: area = (sqrt(3)/4) * s^2 where s is the length of one side of the triangle. If the length of one side of the triangle is 6 cm, the area of the triangle is: area = (sqrt(3)/4) * 6^2 = (sqrt(3)/4) * 36 = (3.46/4) * 36 = 13.83 * 36 = 498.68 Rounded to one decimal place, the area of the triangle is approximately 499 cm^2.
