(x - 1)/(x2 + x) = infinity
In order to find this approach to infinity, we have to see what creates this jumbled mess. For it to approach infinity, the denominator must be 0. Therefore:
x2 + x = 0
x(x + 1) = 0
x1 = 0
x2 = -1
Thus, when limx=>0(x-1)/(x2 + x) = inf
Or, when limx=>-1(x-1)/(x2 + x) = inf
When the denominator is equal to zero, the expression is undefined. Close to those places, the expression tends towards plus infinity, or minus infinity. In other words, setting the denominator to zero will tell you where there are vertical asymptotes.
Yes, to the left (towards minus infinity).Yes, to the left (towards minus infinity).Yes, to the left (towards minus infinity).Yes, to the left (towards minus infinity).
I believe the maximum would be two - one when the independent variable tends toward minus infinity, and one when it tends toward plus infinity. Unbounded functions can have lots of asymptotes; for example the periodic tangent function.
f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
It means minus.
The term "4.23 plus 16.21" matches with definition A) 26.09. The term "42.3 plus 1.621" matches with definition B) 43.921. The term "4.23 and minus 1.621" matches with definition C) 20.44. The term "42.3 and minus 16.21" matches with definition D.
You can't really take that power, but you can take the limit - meaning you can see what happens when the exponent gets closer and closer to "minus infinite". That limit is zero.
Vertial Speed is final depth minus intitial depth divided by time
No. An angle is (90 minus its complement) degrees. The definition of the complement is "90 degrees minus the original angle".
adding and subtracting integers is when you add and minus 2 numbers
pH of a solution is the negative logarithm of the hydrogen-ion concentration
Yeah, that's valid, but it's almost always the worst possible way to go about solving a question. Any functions which are complicated enough to be worth showing have limits are usually too complicated to do it that way.