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(x - 1)/(x2 + x) = infinity

In order to find this approach to infinity, we have to see what creates this jumbled mess. For it to approach infinity, the denominator must be 0. Therefore:

x2 + x = 0

x(x + 1) = 0

x1 = 0

x2 = -1

Thus, when limx=>0(x-1)/(x2 + x) = inf

Or, when limx=>-1(x-1)/(x2 + x) = inf

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