moles of Al=4.40 g/26.9815 g/mol=0.163
moles cl2=15.4g/70.906g/mol=0.217
the ratio is 2:3
cl2 is the limiting reagent
2Al + 3Cl2 ---> 2AlCl3
Products
single displacement 2AlI3+3Cl2-->2AlCl3+3I2
1313
2Al + 3Cl2 -> 2AlCl3
2AlCl3 ---> 2Al + 3Cl2
3
2AlBr3+3Cl2 --> 2AlCl3+3Br2
2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2
2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2
Correctly written it is 2Al(s) + 3Cl2(g) = 2AlCl3(s)
2 AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2