It depends on the way in which the circle function is defined by the user. It also depends on the way in which the graphing utility implements the instruction.
the center of curvature is the ORIGIN of the radius of curvature
Centre = (0,0), the origin; radius = 11
The Origin ( or just "origin") * * * * * That is not generally true. The general formula for a circle, in the Cartesian plane, is of the form (x-a)2 + (y-b)2 = r2 where the coordinates of the centre are (a,b) and the radius is r. It is only if both a and b are 0 that the centre is the origin.
The one in which the centre is in the fourth quadrant, and where the distance from the centre of the circle to the origin is greater than its radius.
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
x2 + y2 = 25 A circle with centre (xo, yo) and radius r has equation: (x - xo)2 + (y - yo)2 = r2 So with centre the origin (0, 0) and radius 5 cm, the circle has equation: (x - 0)2 + (y - 0)2 = 52 ⇒ x2 + y2 = 25
Either.... Halve the diameter; or Divide the circumference by 2pi; or Calculate the difference between the location fo the centre and the location of a point on the circumference.
The distance from any point on the circle to the origin
It is the circular disc with centre at the origin and radius = 3 units.
Formula for a circle with centre (xo, yo) and radius r is: (x - xo)2 + (y - yo)2 = r2 Circle centre (0, 0) and radius 14: (x - 0)2 + (y - 0)2 = 142 x2 + y2 = 196
Centre is 169 and Radius is 84.5
4 is a number. It does not have a centre, not a radius.