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(2x + 8) / (3x - 9) + (3x + 12) / (x2 - 9)

= 2(x + 4) / 3(x - 3) + 3(x + 4) / (x + 3)(x - 3)

= [ 2(x + 4)(x + 3) + 9( x + 4 ) ] / 3(x + 3)(x - 3)

= [ 2( x2 + 7x + 12 ) + 9x + 36 ] / 3(x + 3)(x - 3)

= (2x2 + 23x + 48) / 3(x + 3)(x - 3)

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14y ago
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Q: What is the lowest terms this can be written in 2x plus 8 divided by3x-9 plus 3x plus 12 divided by x2-9?
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