0
What is the magnitude of an object if it is vector a is 5m and vector b is 3.5 m?
Wiki User
∙ 12y ago
any length between 1.5 and 8.5 meters depending on the angle between the vectors.
find the dot product of the two vectors to find the magnitude.
e.g. two vectors
a x
b . y
c z
gives a.x+b.y+c.z= your final answer. The dots mean times by (btw)
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
What is 7M x 5M?
35 m2
How far will an object move in one second if its average speed is 5?
5m/s
Why can 5 m and 35 cm can be written 5.35 m?
Centi is a factor of one hundredth; therefore 35 cm is .35m. Add 5m and .35 m is 5.35m.
-7m-3m plus 5m?
-7m - 3m + 5m = -5m
What is the solution to 5m equals 40?
5m = 40m = 40/5m = 8
Is 5m a vector?
If a direction is given, it is a vector. Otherwise it is a scalar.
A 100kg man is hanging 5m above the horizontal ground.What magnitude of weight of the man?
The magnitude of the weight of the man is 980N.
What is 7M x 5M?
35 m2
Displacement vectors of 3m and 5m in the same direction combine to make a displacement vector that is?
2 m
By the time you have lifted the object 5m off the ground how much rope have you pulled through the pully?
10m
What is the velocity of an object that travels 50m in 10s?
5m/s
What does m -5m -35?
30
How much work is done in lifting a 50kg object to height of 5m?
anser
How far will an object move in one second if its average speed is 5?
5m/s
Why can 5 m and 35 cm can be written 5.35 m?
Centi is a factor of one hundredth; therefore 35 cm is .35m. Add 5m and .35 m is 5.35m.
What is the answer -5m equals -35?
30
Does a unit vector have direction?
No it doesn't. A unit vector indicates direction only. The length of the orthogonal components are RELATIVE to the absolute length of the vector, thus cannot have a unit. For instance, let X'=X/x where X is a vector, x is a scalar and X' is a unit vector. X has length and direction and x has length only, thus X' has direction only. Here's an example. C = A + B where A=3m*A' and B=4m*B' (where A and B are orthogonal) cC' = aA' + bB' C' = (a/c)A' + (b/c)B' = xA' + yB' c = sqrt(3m^2+4m^2) = 5m (by pythagorous) x = (3m/5m) = (3/5) (notice that the units cancel out!) y = (4m/5m) = (4/5) (notice that the units cancel out!)
