Q: What is the mass in grams of 27 mL of pure water?

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This is simple math. Density=Mass(grams)/Volume(milliliters) so since 3^3=27 then it works out to a simple D=54/27 aka 2. 2kg/L to be exact.

The atomic weight of copper is 63.546 grams per mole. 129 kg is equal to 129000 grams. So there are 2030.03 moles of copper. There are 6.022 x 10^23 copper atoms in a mole. So there are 12.22 x 10^26 atoms.

There are 1000 milligrams in one gram. Therefore, 27 grams is equal to 27 x 1000 = 27000 milligrams.

It is 27 grams.

Density = mas/volume = 12 g/27 cc = 0.44... recurring grams per cubic centimetre.

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The density is the mass per unit volume. So, the density = 27/10 = 2.7 grams/cc

6.705909598079999e+27 grams

27 gm of water is about 1.9 tbsp

27 g Na + H2O = 40 g NaOH + 3 g H2. Law of Conservation of Mass. The reactants must have the same number of grams of the products. 40 + 3 = 43. 43 - 27 = 16 g H2O.

There are 1.5 moles water in 27 grams

The mass of 1 proton is 1.6726219 × 10-27 kilograms

Go to the Wikipedia, and look up the mass in kilograms. Then multiply that by 1000 to convert to grams. (Since you will find the number in scientific notation, this means adding 3 to the exponent.)

7 X 102 g Al this is the awnser using significant figures

Not sure that anything has a volume of a cubic centremeter, since there is no such measure. Cubic centimetre, yes. Density = Mass/Volume = 27 g / 10 cc = 2.7 grams per centimetre.

2.7 gram per cubic centimeter

About 907.2 grams.

The mass of a proton is 1.672 621777(74)x 10 to the power of -27, in grams.