Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (atomic mass units) step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr amu on your periodic table is grams when you have one mol of that substance
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
You have :N2 + O2 -----> 2NOmoles NO = ( 2 mols N2 reacted ) ( 2 mol NO / mol N2 reacted )moles NO = 4 moles NOmass NO = ( 4 mol NO ) ( 30 g NO / mol NO ) = 120 g NO
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
mol = mass/Mr rearrange mol x Mr = mass 2 x 126.9g = 253.8g
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
Ca = 40 x 3 = 120 grams P = 31 x 2 = 62 grams O = 16 x 8 = 128 grams Add them together and you have 310 grams. This is the mass in grams of your formula. It is expressed in grams/mole because 310 is the weight of one mole of Ca3(PO4)2.
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (atomic mass units) step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr amu on your periodic table is grams when you have one mol of that substance
0.8 moles HNO3 (63.018 grams/1 mole HNO3) = 50 grams nitric acid ===============
The formula of acetic acid is NOT CHCOOH but CH3COOH which also is found back in the corrected molar mass:The total molecular mass. 12.01 gC/mol + (3 *1.008) gH/mol + 12.01 gC/mol + 2*16.00 gO/mol + 1.008 gH/mol = 60.05 grams per mole
You have :N2 + O2 -----> 2NOmoles NO = ( 2 mols N2 reacted ) ( 2 mol NO / mol N2 reacted )moles NO = 4 moles NOmass NO = ( 4 mol NO ) ( 30 g NO / mol NO ) = 120 g NO
249.72 g/mol
You calculate it by using Avogadro's number: 6.022 x10 23 which is one mole of substance. 1.00 x 1024 divided by 6.022 x 1023 = 10 divided by 6.022 = 1.661 mol H2O Use the molar mass of water (18.02 g mol-1) to get to the mass in grams. 18.02 g x 1.661 mol = 29.93 g H2O
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.00 moles Al × (27.0 grams) = 54.0 grams Al
What is cacl2ything? Molar mass of CaCl2 is 111 g/mol Best guess for an answer to your confusing question is 4.79 x 10-2 mole x 111 g/mole = 5.3169 grams
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g